The correct order of decreasing electronegatıvity values among the elements I-beryllium, II-oxygen,…
- II $>\mathrm{III}>\mathrm{I}>\mathrm{IV}$
- $\mathrm{III}>\mathrm{IV}>\mathrm{II}>\mathrm{I}$
- $\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}$
- $\quad \mathrm{I}>\mathrm{II}>\mathrm{IV}>\mathrm{III}$
Solution
$\mathrm{Be}-1.5(\mathrm{I}) \quad \mathrm{Mg}-1.2(\mathrm{IV})$
$\begin{array}{ll}\mathrm{O}-3.5 \text { (II) } & \mathrm{N}-3.0 \text { (III) }\end{array}$
i.e. $\mathrm{II}>\mathrm{III}>\mathrm{I}>\mathrm{IV}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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