The correct order of bond angles of the following is $\begin{array}{cccc}\mathrm{H}_2 \mathrm{O} &…

The correct order of bond angles of the following is $\begin{array}{cccc}\mathrm{H}_2 \mathrm{O} & \mathrm{NH}_3 & \mathrm{CH}_4 & \mathrm{SO}_2 \\ \text { I } & \text { II } & \text { III } & \text { IV }\end{array}$
  1. IV $>$ III $>$ II $>$ I
  2. IV $>$ III $>$ I $>$ II
  3. I $>$ II $>$ III $>$ IV
  4. I $>$ II $>$ IV $>$ III

Solution



The bond angles are determined on the basis of hybridization of the central atom and the number of lone pairs and bond pairs that cause the repulsion and affect the bond angle. Thus, bond angle varies as IV $>$ III $>$ II $>$ I.

Asked in: AP EAMCET 2023 (16 May Shift 1)

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