The correct order of basicity of the given compounds is

The correct order of basicity of the given compounds is
  1. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2} < \mathrm{HO}\left(\mathrm{CH}_{2}ight)_{3} \mathrm{NH}_{2} < \mathrm{HO}\left(\mathrm{CH}_{2}ight)_{2} \mathrm{NH}_{2}$
  2. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2} < \mathrm{HO}\left(\mathrm{CH}_{2}ight)_{3} \mathrm{NH}_{2}>\mathrm{HO}\left(\mathrm{CH}_{2}ight)_{2} \mathrm{NH}_{2}$
  3. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}>\mathrm{HO}\left(\mathrm{CH}_{2}ight)_{3} \mathrm{NH}_{2}>\mathrm{HO}\left(\mathrm{CH}_{2}ight)_{2} \mathrm{NH}_{2}$
  4. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}>\mathrm{HO}\left(\mathrm{CH}_{2}ight)_{3} \mathrm{NH}_{2} < \mathrm{HO}\left(\mathrm{CH}_{2}ight)_{2} \mathrm{NH}_{2}$

Solution

The $-$ OH group causes decrease in the basicity of $-\mathrm{NH}_{2}$ group.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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