The correct order of acidic strength is

The correct order of acidic strength is
  1. $\mathrm{Cl}_{2} \mathrm{O}_{7}>\mathrm{SO}_{3}>\mathrm{P}_{4} \mathrm{O}_{10}$
  2. $\mathrm{CO}_{2}>\mathrm{N}_{2} \mathrm{O}_{4}>\mathrm{SO}_{3}$
  3. $\mathrm{Na}_{2} \mathrm{O}>\mathrm{MgO}>\mathrm{Al}_{2} \mathrm{O}_{3}$
  4. $\mathrm{K}_{2} \mathrm{O}>\mathrm{CaO}>\mathrm{MgO}$

Solution

The acidic strength of an acid is defined as the tendency of the acid to dissociate into its corresponding ions in order to release a proton and the anion. The acidic strength of a strong acid is high and that of a weak acid is low. This means that on dissociation, a strong acid releases its proton at a much faster rate than the weak acid.
Oxidation number: The greater the oxidation number of the central atom of the oxide, the greater the acidic strength will be.
In a periodic table, the acidic strength of an atom increases across a period and decreases down the group. In the above options, the correct order of acidic strength of the oxides is:
$\mathrm{Cl}_{2} \mathrm{O}_{7}>\mathrm{SO}_{3}>\mathrm{P}_{4} \mathrm{O}_{10}$
The oxidation state of the oxides is as follows:
Let the oxidation number of the chlorine atom be ' $x^{\prime}$.
$\mathrm{Cl}_{2} \mathrm{O}_{7}=2 x+7(-2) ightarrow x=+7$
Let the oxidation number of the sulfur atom be $^{\prime} y^{\prime}$.
$S O_{3}=y+3(-2) \Rightarrow y=+6$
Let the oxidation number of the phosphorus atom be ${ }^{\prime} z^{\prime}$.
$P_{4} O_{10}-4 z+10(-2) ightarrow z-+5$
Thus, as we can see that the order of oxidation is in a decreasing manner, this means that this option is correct.
So, the correct answer is Option $(a)$.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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