The correct electronic configuration of the element $\mathrm{Au}$ is
The correct electronic configuration of the element $\mathrm{Au}$ is
- $[\mathrm{Xe}] 4 f^{14} 5 d^{10} 6 s^2$
- $[\mathrm{Xe}] 4 f^{14} 5 d^9 6 s^2$
- $[\mathrm{Xe}] 4 f^{14} 5 d^{10} 6 s^1$
- $[X e] 4 f^{14} 5 d^9 6 s^1$
Solution
The electronic configuration of the element $\mathrm{Au}$ is [Xe] $4 f^{14} 5 d^{10} 6 s^1$
Asked in: AP EAMCET 2022 (08 Jul Shift 2)
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