The correct decreasing order of atomic radii $(\mathrm{pm})$ of $\mathrm{Li}, \mathrm{Be}, \mathrm{B}$ and C…

The correct decreasing order of atomic radii $(\mathrm{pm})$ of $\mathrm{Li}, \mathrm{Be}, \mathrm{B}$ and C is
  1. $\mathrm{Be}\gt\mathrm{Li}\gt\mathrm{B}\gt\mathrm{C}$
  2. $\mathrm{Li}\gt\mathrm{Be}\gt\mathrm{B}\gt\mathrm{C}$
  3. $\mathrm{C}\gt$ B $\gt$ Be $\gt\mathrm{Li}$
  4. $\mathrm{Li}\gt\mathrm{C}\gt\mathrm{Be}\gt\mathrm{B}$

Solution

As the atomic number in a period increases, the effective nuclear charge also increases hence, atomic radii along the period decreases. Correct order of atomic radii $\mathrm{Li}\gt\mathrm{Be}\gt\mathrm{B}\gt\mathrm{C}$

Asked in: NEET 2024 (Re-NEET)

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