The correct Biot- Savart law in vector form is

The correct Biot- Savart law in vector form is
  1. \(\overline{\delta B}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{dl}(\overrightarrow{\mathrm{l}} \times \overrightarrow{\mathrm{r}})}{\mathrm{r}^{3}}\)
  2. \(\overline{\delta \mathrm{B}}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}(\overrightarrow{\mathrm{d} l} \times \overrightarrow{\mathrm{r}})}{\mathrm{r}^{3}}\)
  3. \(\overline{\delta \mathrm{B}}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}(\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{d} l})}{\mathrm{r}^{3}}\)
  4. \(\overline{\delta \mathrm{B}}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}(\overrightarrow{\mathrm{d} l} \times \overrightarrow{\mathrm{r}})}{\mathrm{r}^{2}}\)

Solution

Biot - Savart law describes magnetic field created by a current carrying conductor. Biot - Savart law in vector form is
\( d \vec{B}=\frac{\mu_{0}}{4 I I} \frac{I(d \vec{l} \times \vec{r})}{r^{3}} \) .

Asked in: MHT CET Full Test 4

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