The coordination number and the oxidation state of the element ' $\mathrm{E}$ ' in the complex…

The coordination number and the oxidation state of the element ' $\mathrm{E}$ ' in the complex $\left[\mathrm{E}(\mathrm{en})_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2$ (where (en) is ethylene diamine) are, respectively,
  1. 6 and 2
  2. 4 and 2
  3. 4 and 3
  4. 6 and 3

Solution


$ \text { Coordination no. }=6 \text { and Oxidation no. }=3 $

Asked in: JEE Main 2008

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