The coordination environment of \(\mathrm{Ca}^{2+}\) ion in its complex with \(\mathrm{EDTA}^{4-}\) is :
The coordination environment of \(\mathrm{Ca}^{2+}\) ion in its complex with \(\mathrm{EDTA}^{4-}\) is :
- tetrahedral
- trigonal prismatic
- octahedral
- square planar
Solution
$\begin{aligned} & \text { EDTA }^{4-} \rightarrow \text { Hexadentate ligand } \\ & {[\mathrm{Ca}(\text { EDTA })]^{2-}}\end{aligned}$
So Coordination environment is octahedral
Asked in: JEE Main 2024 (09 Apr Shift 2)
Practice more Coordination Compounds questions on Aicharya