The coordination environment of \(\mathrm{Ca}^{2+}\) ion in its complex with \(\mathrm{EDTA}^{4-}\) is :

The coordination environment of \(\mathrm{Ca}^{2+}\) ion in its complex with \(\mathrm{EDTA}^{4-}\) is :
  1. tetrahedral
  2. trigonal prismatic
  3. octahedral
  4. square planar

Solution

$\begin{aligned} & \text { EDTA }^{4-} \rightarrow \text { Hexadentate ligand } \\ & {[\mathrm{Ca}(\text { EDTA })]^{2-}}\end{aligned}$ So Coordination environment is octahedral

Asked in: JEE Main 2024 (09 Apr Shift 2)

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