The converse of $[p \wedge(\sim q)] \rightarrow r$ is
The converse of $[p \wedge(\sim q)] \rightarrow r$ is
- $\sim \mathrm{r} \rightarrow(\sim \mathrm{p} \vee \mathrm{q})$
- $\mathrm{r} \rightarrow(\sim \mathrm{p} \wedge \sim \mathrm{q})$
- $\quad(\sim p \vee q) \rightarrow \sim r$
- $\quad \mathrm{r} \rightarrow(\mathrm{p} \wedge \mathrm{q})$
Solution
$\begin{aligned}
& \text { Converse of }[p \wedge(\sim q)] \rightarrow r \\
& =\sim[p \wedge(\sim q)] \rightarrow \sim r \\
& =(\sim p \vee q) \rightarrow \sim r
\end{aligned}$
...[De morgans Law]
Asked in: MHT CET 2024 (04 May Shift 2)
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