The conjugate base of $\mathrm{H}_2 \mathrm{PO}_4^{-}$is

The conjugate base of $\mathrm{H}_2 \mathrm{PO}_4^{-}$is
  1. $\mathrm{PO}_4^{3-}$
  2. $\mathrm{HPO}_4^{2-}$
  3. $\mathrm{H}_3 \mathrm{PO}_4$
  4. $\mathrm{P}_2 \mathrm{O}_5$

Solution

$\because 6.02 \times 10^{+20}$ molecules of urea is present in $=\frac{0.0001 \times 1000}{100}=0.01 \mathrm{M}$

Asked in: JEE Main 2004

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