The conductivity of $0.04 \mathrm{M} \mathrm{BaCl}_2$ solution is $0.0112 \Omega^{-1} \mathrm{~cm}^{-1}$ at…

The conductivity of $0.04 \mathrm{M} \mathrm{BaCl}_2$ solution is $0.0112 \Omega^{-1} \mathrm{~cm}^{-1}$ at $25^{\circ} \mathrm{C}$. what is it's molar conductivity?
  1. $357.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  2. $140.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  3. $44.8 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  4. $280.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

Solution

$\Lambda_{\mathrm{m}}=\frac{\mathrm{k} \times 1000}{\mathrm{M}}$ Conductivity $(\mathrm{k})=0.0112 \Omega^{-1} \mathrm{~cm}^{-1}$ $\begin{aligned} & \Lambda_{\mathrm{m}}=\frac{0.0112 \times 1000}{0.04} \\ & =280 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1} \end{aligned}$

Asked in: MHT CET 2021 (23 Sep Shift 1)

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