The conductivity of $0.20 \mathrm{M} \mathrm{KCl}$ solution at $300 \mathrm{~K}$ is $0.0248 \Omega^{-1}…

The conductivity of $0.20 \mathrm{M} \mathrm{KCl}$ solution at $300 \mathrm{~K}$ is $0.0248 \Omega^{-1} \mathrm{~cm}^{-1}$. What is its molar conductivity?
  1. $124 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  2. $93 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  3. $62 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  4. $186 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

Solution

$\begin{aligned} \Lambda_{\mathrm{m}} & =\frac{\mathrm{k} \times 1000}{\mathrm{M}} \\ & =\frac{0.0248 \times 1000}{0.2} \\ & =124 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\end{aligned}$

Asked in: MHT CET 2022 (06 Aug Shift 2)

Practice more Electrochemistry questions on Aicharya