The conductivity of centimolar solution of KCl at 25 ° C is 0 . 0210 ohm - 1 cm - 1 and the resistance of…

Conductivity$\left(\kappa \right)=0.0210 {\mathrm{ohm}}^{-1}{\mathrm{cm}}^{-1}$

Resistance$\left(\mathrm{R}\right)=60 \mathrm{ohm}$

The relation between specific conductance or conductivity and resistance is 

$\kappa =\frac{1}{\mathrm{R}}\frac{l}{a}$

In the above equation $\frac{l}{a}$ is the cell constant.

$\frac{l}{a}=\kappa \times \mathrm{R}$

$\Rightarrow \frac{\mathit{l}}{\mathit{a}}=0.0210\times 60=1.26 {\mathrm{cm}}^{-1}$