The conductivity of $0.001 \mathrm{M}$ acetic acid at a certain temperature is $5.07 \times 10^{-5}…

The conductivity of $0.001 \mathrm{M}$ acetic acid at a certain temperature is $5.07 \times 10^{-5} \mathrm{~S} \mathrm{~cm}^{-1}$. If $\wedge_m^0$ of acetic acid at the same temperature is $390 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$, the dissociation constant of acetic acid at that temperature is:
  1. $1.94 \times 10^{-5}$
  2. $1.94 \times 10^{-3}$
  3. $1.94 \times 10^{-4}$
  4. $1.94 \times 10^{-6}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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