The conductivity of a semiconductor sample having electron concentration of $5 \times 10^{18} electrons m^{- 3}$ , hole concentration of $5 \times 10^{19} holes m^{- 3}$ , electron mobility of $2 .0 m^{2} V^{- 1} s^{- 1}$ and hole mobility of $0.01 m^{2} V^{- 1} s^{- 1}$ is

(Take charge of an electron as $1 .6 \times 10^{- 19} C$ )

Question

The conductivity of a semiconductor sample having electron concentration of

5 \times 10^{18} electrons m^{- 3}

, hole concentration of

5 \times 10^{19} holes m^{- 3}

, electron mobility of

2 .0 m^{2} V^{- 1} s^{- 1}

and hole mobility of

0.01 m^{2} V^{- 1} s^{- 1}

is

(Take charge of an electron as

1 .6 \times 10^{- 19} C

)

Aicharya · Accepted Answer

The conductivity of a semiconductor is given by

$σ = e (n_{e} μ_{e} + n_{h} μ_{h})$

$= 1 .6 \times 10^{- 19} (5 \times 10^{18} \times 2 + 5 \times 10^{19} \times 0 .01)$

$= 1.6 \times 10^{- 19} (10^{19} + 0.05 \times 10^{19})$

$= 1.6 + 1.05$

$= 1 .65 {(Ω m)}^{- 1}$

The conductivity of a semiconductor sample having electron concentration of 5 × 10 18   electrons…

Solution

The conductivity of a semiconductor sample having electron concentration of 5 &#215; 10 18 &#160; electrons…

Solution

The conductivity of a semiconductor sample having electron concentration of 5 × 10 18 electrons…