The conductivity of 0.02 M KCl , solution is $0.00250 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$. What is its…
The conductivity of 0.02 M KCl , solution is $0.00250 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$. What is its molar conductivity?
- $125 \mathrm{ohm}^{-1} \mathrm{~cm}^{-2} \mathrm{~mol}^{-1}$
- $0.05 \mathrm{ohm}^{-1} \mathrm{~cm}^{-2} \mathrm{~mol}^{-1}$
- $725 \mathrm{ohm}^{-1} \mathrm{~cm}^{-2} \mathrm{~mol}^{-1}$
- $8000 \mathrm{ohm}^{-1} \mathrm{~cm}^{-2} \mathrm{~mol}^{-1}$
Solution
$\begin{aligned} & \text { Molar conductivity } \begin{aligned} & =\frac{1000 \mathrm{k}}{\mathrm{c}} \\ & =\frac{1000 \mathrm{~cm}^3 \mathrm{~L}^{-1} \times 0.00250 \Omega^{-1} \mathrm{~cm}^{-1}}{0.02 \mathrm{molL}^{-1}} \\ = & 125 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\end{aligned}\end{aligned}$
Asked in: MHT CET 2024 (11 May Shift 1)
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