The conductance of 0 .0015   M aqueous solution of a weak monobasic acid was determined by using a…

The conductance of 0.0015 M aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized Pt electrodes. The distance between the electrodes is 120 cm with an area of cross-section of 1 cm2. The conductance of this solution was found to be 5×10-7S . The pH of the solution is 4. The value of limiting molar conductivity of this weak monobasic acid in aqueous solution is  Z × 102S cm-1mol-1. The value of Z is.

Solution

For weak acid, H+=cα=c×∧mc∧m∞

=c×k×1000c∧m∞=k×1000∧m∞=G×la×1000∧m∞

10-4=5×10-71201×1000Z×102 ⇒ Z=6

Asked in: JEE Advanced 2017 (Paper 1)

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