The condition that f ( x ) = a x 3 + b x 2 + c x + d has no extreme value, is

The condition that f(x)=ax3+bx2+cx+d has no extreme value, is
  1. b2>3ac
  2. b2=4ac
  3. b2=3ac
  4. b2<3ac

Solution

Given curve is f(x)=ax3+bx2+cx+d

On differentiating w.r.t. x, we get

f'(x)=3ax2+2bx+c

For extremum, f'(x)=03ax2+2bx+c=0

Since, it has no extremum value.

Discriminant<0

(2b)2-4×3a×c<0

4b2-12ac<0b2-3ac<0

b2<3ac

Asked in: AP EAMCET 2022 (04 Jul Shift 1)

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