The compound which have the same magnetic moment like that of $\mathrm{FeCl}_{2}$ is
- $\mathrm{CrCl}_{3}$
- $\mathrm{MnCl}_{2}$
- $\mathrm{CoCl}_{3}$
- $\mathrm{NiCl}_{2}$
Solution

four unpaired electrons.
Only $\mathrm{CoCl}_{3}$ has a similar configuration $3 \mathrm{d}^{6} 4 \mathrm{s}^{0}$ and therefore four unpaired electrons. *
Asked in: JEE-TOPICTESTS-CHEMISTRY
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