The compound $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{2}ight.$ (en) $\left.\mathrm{Cl}_{2}ight]$ can form

The compound $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{2}ight.$ (en) $\left.\mathrm{Cl}_{2}ight]$ can form
  1. linkage isomers
  2. coordination isomers
  3. optical isomers
  4. linkage as well as optical isomers

Solution

The compound $\left[\mathrm{CoCl}_{2}\left(\mathrm{NH}_{3}ight)_{2}(\mathrm{en})ight]$ has two geometrical isomers. One is the cis-isomer (with respect to $\mathrm{NH}_{3}$ ) and the other is the trans- isomer (with respect to $\mathrm{NH}_{3}$ ).
The cis-isomer has two optically active forms, $\mathrm{d}$-cis isomer and $\mathrm{l}$-cis isomer. So, the compound $\left[\mathrm{CoCl}_{2}\left(\mathrm{NH}_{3}ight)_{2}ight.$ (en)] can form geometrical isomers as well as optical isomers.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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