The complex ion that will lose its crystal field stabilization energy upon oxidation of metal to + 3 state is:

The complex ion that will lose its crystal field stabilization energy upon oxidation of metal to $+3$ state is:

1. ${\left[\mathrm{Ni}{\left(\mathrm{p}\mathrm{h}\mathrm{e}\mathrm{n}\right)}_3\right]}^{2+}$
2. ${\left[\mathrm{F}\mathrm{e}{\left(\mathrm{p}\mathrm{h}\mathrm{e}\mathrm{n}\right)}_3\right]}^{2+}$
3. ${\left[\mathrm{C}\mathrm{o}{\left(\mathrm{p}\mathrm{h}\mathrm{e}\mathrm{n}\right)}_3\right]}^{2+}$
4. ${\left[\mathrm{Zn}{\left(\mathrm{p}\mathrm{h}\mathrm{e}\mathrm{n}\right)}_3\right]}^{2+}$

Solution

Asked in: JEE Main 2019 (12 Apr Shift 1)

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