The complex(es), which can exhibit the type of isomerism shown by Pt NH 3 2 Br 2 , is(are) en = H 2 NCH 2 CH…

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_2\right]$ is a square planar complex and it can exhibit geometrical isomerism. It has two isomers, cis-platin and trans-platin. The complexes $\left[\mathrm{Zn}{\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_2\right] \left(\mathrm{tetrahedral}\right) \mathrm{and} \left[\mathrm{Pt}\left(\mathrm{en}\right)(\mathrm{SCN}{)}_2\right]$ does not exhibit geometrical isomerism. The octahedral complex $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_4\right]$ shows geometrical isomerism, it has two geometrical isomers cis and trans.

 ${\left[\mathrm{Cr}(\mathrm{en}{)}_2\left({\mathrm{H}}_2\mathrm{O}\right)\left({\mathrm{SO}}_4\right)\right]}^{+}$ is an octahedral complex, it is of the type $\mathrm{M}{\left(\mathrm{AA}\right)}_2\mathrm{bc}$ and it can exhibit the geometrical isomerism.