The complex conjugate of $(4-3 i)(2+3 i)(1+4 i)$ is

The complex conjugate of $(4-3 i)(2+3 i)(1+4 i)$ is
  1. $7+74 i$
  2. $-7+74 i$
  3. $-7-74 i$
  4. $7-74 i$

Solution

$\begin{aligned} & \text { }(4-3 i)(2+3 i)(1+4 i)=(4-3 i)(-10+11 i) \\ & =-40+44 i+30 i+33=-7+74 i \end{aligned}$
Complex conjugate $=-7-74 i$

Asked in: AP EAMCET 2024 (21 May Shift 1)

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