The coefficient of x 9 in the expansion of 1 + x   1 + x 2   1 + x 3 … … 1 + x 100 is

The coefficient of x9 in the expansion of 1+x 1+x2 1+x31+x100 is

Solution

1+x 1+x2.(1+x100)
Possible combination of 9 are (0, 9), (1, 8), (2, 7), (3, 6), (4, 5), (1, 2, 6), (1, 3, 5), (2, 3, 4)
So, coefficient = 8.

Asked in: JEE Advanced 2015 (Paper 2)

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