The coefficient of static friction $\mu_8$, between block $A$ of mass $2 \mathrm{~kg}$ and the table as…
The coefficient of static friction $\mu_8$, between block $A$ of mass $2 \mathrm{~kg}$ and the table as shown in the figure is 0.2 . What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless $(g$ $\left.=10 \mathrm{~m} / \mathrm{s}^2\right)$
$2.0 \mathrm{~kg}$
$4.0 \mathrm{~kg}$
$0.2 \mathrm{~kg}$
$0.4 \mathrm{~kg}$
Solution
According to the question
$T=m_{\mathrm{B}} q=\mu\left(m_{\mathrm{A}} q\right)$
$\begin{aligned}
\Rightarrow \quad m_{\mathrm{B}} & =\mu m_{\mathrm{A}}=0.02 \times 2 \\
& =0.4 \mathrm{~kg}
\end{aligned}$
$\begin{aligned}
\Rightarrow \quad m_{\mathrm{B}} & =\mu m_{\mathrm{A}}=0.02 \times 2 \\
& =0.4 \mathrm{~kg}
\end{aligned}$