The coefficient of mutual inductance between the primary and the secondary coil of a transformer is \(0.2…

The coefficient of mutual inductance between the primary and the secondary coil of a transformer is \(0.2 \mathrm{H}\). When the current in the primary changes by \(5 \mathrm{As}^{-1}\), then the induced emf in the secondary will be
  1. \(5 \mathrm{~V}\)
  2. \(1 \mathrm{~V}\)
  3. \(25 \mathrm{~V}\)
  4. \(10 \mathrm{~V}\)

Solution

Given, coefficient of mutual induction, \(M=0.2 \mathrm{H}\) The rate of change in current in primary coil. \(\frac{d I}{d t}=5 \mathrm{As}^{-1}\) \(\therefore\) Induced emf in the secondary coil, \(e=M \frac{d I}{d t}=0.2 \times 5=1 \mathrm{~V}\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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