The COD of water sample is determined using
- $50 \% \mathrm{H}_2 \mathrm{SO}_4, \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7$
- $50 \% \mathrm{NaOH}, \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$
- $50 \% \mathrm{CH}_3 \mathrm{COOH}, \mathrm{KMnO}_4$
- $50 \% \mathrm{H}_2 \mathrm{SO}_4, \mathrm{FeSO}_4$
Solution
Asked in: AP EAMCET 2017 (26 Apr Shift 2)