The co-ordinates of the foot of the perpendicular drawn form the origin to the plane $3 x+2 y+6 z=56$ is

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Aicharya · Accepted Answer

$\begin{aligned} & \frac{x-0}{3}=\frac{y-0}{2}=\frac{z-0}{6}=\frac{-(3 	imes 0+2 	imes 0+1 	imes 0-56)}{3^2+2^2+6^2} \ & \Rightarrow \frac{x}{3}=\frac{y}{2}=\frac{z}{6}=\frac{56}{49} \Rightarrow x=\frac{24}{7}, y=\frac{16}{7}, \mathrm{z}=\frac{48}{7} \ & \Rightarrow\left(\frac{24}{7}, \frac{16}{7}, \frac{48}{7}ight)\end{aligned}$

The co-ordinates of the foot of the perpendicular drawn form the origin to the plane $3 x+2 y+6 z=56$ is

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