The co-ordinates of the focus of the parabola $(x+3)^2=2(y-5)$ is

Question

Aicharya · Accepted Answer

$\begin{aligned} & (x+3)^2=2(y-5) \ & \therefore \quad \text {Vertex }=(-3,5), a=\frac{1}{2} \ & \therefore \text {Focus }(s)=\left(-3,5+\frac{1}{2}\right)=\left(-3, \frac{11}{2}\right) \end{aligned}$ Hence, option (b) is correct.

The co-ordinates of the focus of the parabola \((x+3)^2=2(y-5)\) is

Solution