The co-ordinates of focus of the parabola \(5 x^2=-12 y\) are
The co-ordinates of focus of the parabola \(5 x^2=-12 y\) are
- \(\left(\frac{3}{5}, 0\right)\)
- \(\left(\frac{-3}{5}, 0\right)\)
- \(\left(0, \frac{3}{5}\right)\)
- \(\left(0, \frac{-3}{5}\right)\)
Solution
Given Parabola,
\(\begin{aligned}
5 x^2 & =-12 y \quad \Rightarrow x^2=\frac{-12}{5} y \\
4 a & =\frac{-12}{5} \Rightarrow a=\frac{-3}{5} \\
\text { Focus }=(0, a) & =\left(0, \frac{-3}{5}\right)
\end{aligned}\)
Hence, option (d) is correct.
Asked in: AP EAMCET 2020 (18 Sep Shift 2)
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