The circuit is equivalent to

The circuit is equivalent to

1. AND gate
2. NAND gate
3. NOR gate
4. OR gate

Solution

The gate circuit can be shown by giving two inputs $A$ and $B$.

Output of NOR gate,
$Y_1=\overline{A+B}$
Output of NAND gate,
$\begin{aligned}
Y_2 & =\overline{Y_1 \cdot Y_1} \\
& =\overline{\overline{A+B} \cdot \overline{A+B}} \\
& =\overline{\overline{A+B}}+\overline{\overline{A+B}} \\
& =(A+B)+(A+B) \\
& =A+B
\end{aligned}$
Output of NOT gate,
$\begin{aligned}
Y & =\overline{Y_2} \\
& =\overline{A+B}
\end{aligned}$
which is the output of NOR gate.
Alternative :
Same as NOR Gate
NOR Gate
$\begin{array}{lll}0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{array}$

Asked in: NEET 2008 (Screening)

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