The circuit has two oppositely connect ideal diodes in parallel. What is the current following in the circuit?
The circuit has two oppositely connect ideal diodes in parallel. What is the current following in the circuit?

-
$1.33 \mathrm{~A}$
-
$1.71 \mathrm{~A}$
-
$2.00 \mathrm{~A}$
-
$2.31 \mathrm{~A}$
Solution
$D_1$ is reverse biased therefore it will act like an open circuit.
$
\mathrm{i}=\frac{12}{6}=2.00 \mathrm{~A}
$
Asked in: JEE Main 2006
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