The circuit contains two diodes each with a forward resistance of 50   Ω and with infinite reverse…

In this circuit $D_1$ will be forward bias and $D_2$ will be revers bias.

$\therefore$ There will be no current through $D_2$ and $R_2$

Apply KVL in circuit we get

$+6-50i-130i-120i=0$

$i=\frac{6}{300} \mathrm{A}=\frac{6}{300}\times 1000 \mathrm{mA}$

$\Rightarrow 20 \mathrm{mA}$