The circles $x^2+y^2+2 x+3 y-7=0$ and $x^2+y^2+4 x-7 y+5=0$ intersect at the points $\mathrm{A}$ and…

The circles $x^2+y^2+2 x+3 y-7=0$ and $x^2+y^2+4 x-7 y+5=0$ intersect at the points $\mathrm{A}$ and $\mathrm{B}$. The equation of the circle, having $\overline{\mathrm{AB}}$ as a diameter is
  1. $26 x^2+26 y^2+77 x-47 y+32=0$
  2. $26 x^2+26 y^2+77 x+47 y-32=0$
  3. $26 x^2+26 y^2+77 x-47 y-32=0$
  4. $26 x^2+26 y^2+77 x+47 y+32=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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