
The charge on each capacitor when a voltage source of $15 \mathrm{~V}$ is connected in the circuit as shown,…

- $75 \mu \mathrm{C}$
- $150 \mu \mathrm{C}$
- $30 \mu \mathrm{C}$
- $60 \mu \mathrm{C}$
Solution
All four capacitors are connected in parallel.
$\therefore$ The charge on each capacitor,
$\mathrm{q}=\mathrm{CV}=5 \times 15=75 \mu \mathrm{C}$Asked in: MHT CET 2021 (24 Sep Shift 1)