The CFSE for CoCl 6 4 complex is 18000   cm - 1 . The Δ for CoCl 4 2 - will be:

The CFSE for CoCl64 complex is 18000 cm-1. The Δ for CoCl42- will be:
  1. 8000
  2. 9000
  3. 8100
  4. 7900

Solution

Δt=49Δ0=49×18000=8000 ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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