The centroid of tetrahedron with vertices at $A(-1,2,3), B(3,-2,1), C(2,1,3)$ and $D(-1,-2,4)$ is
The centroid of tetrahedron with vertices at $A(-1,2,3), B(3,-2,1), C(2,1,3)$ and $D(-1,-2,4)$ is
- $\left(\frac{3}{4}, \frac{-1}{4}, \frac{11}{4}\right)$
- $\left(\frac{5}{4}, \frac{-3}{4}, \frac{7}{4}\right)$
- $\left(\frac{-3}{4}, \frac{-1}{4}, \frac{11}{4}\right)$
- $\left(\frac{-5}{4}, \frac{-3}{4}, \frac{-7}{4}\right)$
Solution
Centroid of tetrahedron
$\begin{aligned}
& \equiv\left(\frac{-1+3+2-1}{4}, \frac{2-2+1-2}{4}, \frac{3+1+3+4}{4}\right) \\
& \equiv\left(\frac{3}{4}, \frac{-1}{4}, \frac{11}{4}\right)
\end{aligned}$
Asked in: MHT CET 2023 (12 May Shift 1)
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