The centre of a wheel rolling on a plane surface moves with a speed v 0 . A particle on the rim of the wheel…

The centre of a wheel rolling on a plane surface moves with a speed v0. A particle on the rim of the wheel at the same level as the centre will be moving at a speed xv0. Then the value of x is           .

Solution

For no slipping, v0=ωR
Now, vA=vB=v02+(ωR)2
=2v0

x=2

Asked in: JEE Main 2021 (22 Jul Shift 1)

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