The centre and radius of the circle x 2 + y 2 + 8 x + 10 y - 8 = 0 respectively are

The centre and radius of the circle x2+y2+8x+10y-8=0 respectively are
  1. (-4,-5), 7
  2. (4,5), 49
  3. (-8,-10), 8
  4. (-4,5), 7

Solution

Given that: x2+y2+8x+10y-8=0

As we know that x2+y2+2gx+2fy+c=0

has centre -g,-f and r=g2+f2-c

here, g=4, f=5, c=-8

centre ≡-4,-5,

radius = r = 16+25+8=7

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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