The cell potential for Zn Zn 2 + ( aq ) ‖ Sn x + Sn is 0 . 801 V at 298   K . The reaction…

The cell potential for ZnZn2+(aq)‖Snx+Sn is 0.801V at 298 K. The reaction quotient for the above reaction is 10-2. The number of electrons involved in the given electrochemical cell reaction is _____ .
(Given EZn2+∣Zn0=-0.763 V,ESnx+|Sn0=+0.008 V and 2.303RTF=0.06 V)

Solution

E=E0-2.303RTnFlogQ

Here,

E=+0.801 VE0=ECathode∘-EAnode∘Both are SRP valuesE0=0.008--0.763

=+0.771 V

∴0.801=+0.771-0.06nlog10-2

⇒n=4

Asked in: JEE Main 2022 (25 Jul Shift 1)

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