The Cartesian equation of the plane passing through the point A $(7,8,6)$ and parallel to the XY plane is
The Cartesian equation of the plane passing through the point A $(7,8,6)$ and parallel to the XY plane is
$z=1$
$y=8$
$x=7$
$z=6$
Solution
The required plane passes through the point $(7,8,6)$ and is parallel to XY plane.
$\therefore$ It is perpendicular to $\mathrm{z}$ axis and direction ratios of $\mathrm{z}$ axis are $0,0,1$.
$\therefore$ Required equation of plane is
$0(\mathrm{x}-7)+0(\mathrm{y}-8)+1(\mathrm{z}-6)=0 \Rightarrow \mathrm{z}=6$