The cartesian equation of the curve given by $x=6 \cos \theta, \quad y=6 \sin \theta$ is
The cartesian equation of the curve given by $x=6 \cos \theta, \quad y=6 \sin \theta$ is
$x^{2}+y^{2}=36$
$x^{2}+y^{2}=5$
$x^{2}+y^{2}=25$
$x^{2}+y^{2}=6$
Solution
On squaring and adding both given equations, we get
$\begin{aligned}
x^{2}+y^{2} &=36 \cos ^{2} \theta+36 \sin ^{2} \theta \\
&=36\left(\cos ^{2} \theta+\sin ^{2} \theta\right) \\
x^{2}+y^{2} &=36
\end{aligned}$