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The capacitance of a spherical condenser is \(1 \mu \mathrm{F}\). If the spacing between the two spheres is…
The capacitance of a spherical condenser is \(1 \mu \mathrm{F}\). If the spacing between the two spheres is \(1 \mathrm{~mm}\), the radius of the outer sphere is
\(30 \mathrm{~cm}\) \(6 \mathrm{~m}\) \(5 \mathrm{~cm}\) \(3 \mathrm{~m}\)
Solution
Given, capacitance of spherical capacitor,
\(C=1 \mu \mathrm{F}=10^{-6} \mathrm{~F}\)
Spacing between two spheres of spherical capacitor, \(r_2-r_1=1 \mathrm{~mm}=10^{-3} \mathrm{~m}\)
\(\begin{array}{ll}
\therefore & C=4 \pi \varepsilon_0 \frac{r_1 r_2}{r_2-r_1} \\
\Rightarrow & 10^{-6}=\frac{1}{9 \times 10^9} \times \frac{\left(r_2-10^{-3}\right) r_2}{10^{-3}} \\
\Rightarrow & 9=r_2^2-10^{-3} r_2 \Rightarrow 9000=1000 r_2^2-r_2 \\
\Rightarrow & 1000 r_2^2-r_2-9000=0
\end{array}\)
\(\begin{aligned}
\Rightarrow r_2 & =\frac{-(-1) \pm \sqrt{(-1)^2-4 \times 1000 \times(-9000)}}{2 \times 1000} \\
& =\frac{1 \pm \sqrt{36 \times 10^6}}{2000}=\frac{1 \pm 6000}{2000} \\
& =\frac{1+6000}{2000}=3.0005 \approx 3 \mathrm{~m}
\end{aligned}\)
Asked in: AP EAMCET 2020 (18 Sep Shift 2)
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