The capacitance of a spherical condenser is \(1 \mu \mathrm{F}\). If the spacing between the two spheres is…

The capacitance of a spherical condenser is \(1 \mu \mathrm{F}\). If the spacing between the two spheres is \(1 \mathrm{~mm}\), the radius of the outer sphere is
  1. \(30 \mathrm{~cm}\)
  2. \(6 \mathrm{~m}\)
  3. \(5 \mathrm{~cm}\)
  4. \(3 \mathrm{~m}\)

Solution

Given, capacitance of spherical capacitor, \(C=1 \mu \mathrm{F}=10^{-6} \mathrm{~F}\) Spacing between two spheres of spherical capacitor, \(r_2-r_1=1 \mathrm{~mm}=10^{-3} \mathrm{~m}\) \(\begin{array}{ll} \therefore & C=4 \pi \varepsilon_0 \frac{r_1 r_2}{r_2-r_1} \\ \Rightarrow & 10^{-6}=\frac{1}{9 \times 10^9} \times \frac{\left(r_2-10^{-3}\right) r_2}{10^{-3}} \\ \Rightarrow & 9=r_2^2-10^{-3} r_2 \Rightarrow 9000=1000 r_2^2-r_2 \\ \Rightarrow & 1000 r_2^2-r_2-9000=0 \end{array}\) \(\begin{aligned} \Rightarrow r_2 & =\frac{-(-1) \pm \sqrt{(-1)^2-4 \times 1000 \times(-9000)}}{2 \times 1000} \\ & =\frac{1 \pm \sqrt{36 \times 10^6}}{2000}=\frac{1 \pm 6000}{2000} \\ & =\frac{1+6000}{2000}=3.0005 \approx 3 \mathrm{~m} \end{aligned}\)

Asked in: AP EAMCET 2020 (18 Sep Shift 2)

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