The brown ring test for $\mathrm{NO}_{2}$ and $\mathrm{NO}_{3}$ is due to the formation of complex ion with…

The brown ring test for $\mathrm{NO}_{2}$ and $\mathrm{NO}_{3}$ is due to the formation of complex ion with a formula
  1. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}ight)_{6}ight]^{2+}$
  2. $\left[\mathrm{Fe}(\mathrm{NO})(\mathrm{CN})_{5}ight]^{2+}$
  3. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}ight)_{5} \mathrm{NO}ight]^{2+}$
  4. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}ight)(\mathrm{NO})_{5}ight]^{2+}$

Solution

$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}ight)_{5} \mathrm{NO}ight]^{2+}$ ion is formed

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more P-BLOCK ELEMENTS GROUP 15 16 17 18 questions on Aicharya