The bond stability of \(\mathrm{N}_2, \mathrm{~N}_2^{-}\)and \(\mathrm{N}_2^{2-}\) varies as

The bond stability of \(\mathrm{N}_2, \mathrm{~N}_2^{-}\)and \(\mathrm{N}_2^{2-}\) varies as
  1. \(\mathrm{N}_2 < \mathrm{N}_2^{-} < \mathrm{N}_2^{2-}\)
  2. \(\mathrm{N}_2^{-} < \mathrm{N}_2 < \mathrm{N}_2^{2-}\)
  3. \(\mathrm{N}_2^{2-} < \mathrm{N}_2^{-} < \mathrm{N}_2\)
  4. \(\mathrm{N}_2^{-} < \mathrm{N}_2^{2-} < \mathrm{N}_2\)

Solution

Stability of a molecule is related with bond order as: Stability \(\propto\) Bond order Bond order of \(\mathrm{N}_2, \mathrm{~N}_2^{-}\)and \(\mathrm{N}_2^{-2}\) are 3, 2.5 and 2 respectively. Therefore, the bond stability order is \(\mathrm{N}_2^{-2} < \mathrm{N}_2^{-} < \mathrm{N}_2\). Hence, the correct option is (c).

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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