The bond order values of anions of sodium peroxide and potassium super oxide are respectively.

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Aicharya · Accepted Answer

The peroxide ion in sodium peroxide is $\mathrm{O}_2^{2-}$ has total of 18 electrons. Electronic configuration of $\mathrm{O}_2^{2-}$ is $\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \pi 2 p_z^2, \pi 2 p_x^2 \approx \pi 2 p_y^2$,$\pi^* 2 p_x^2 \approx \pi^* 2 p_y^2$ Bond order $\begin{aligned} & =\frac{1}{2}\left[\begin{array}{l}	ext { No. of bonding }- 	ext { No. of non-bonding } \ 	ext { orbital electrons orbital electrons }\end{array}ight] \ & =\frac{1}{2}[10-8]=1\end{aligned}$ The superoxide in potassium superoxide is $\mathrm{O}_2^{-}$has total of 17 electrons. Electronic configuration of $\mathrm{O}_2^{-}$is $\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \pi 2 p_z^2, \pi 2 p_x^2 \approx \pi 2 p_y^2$,$\pi^* 2 p_x^2 \approx \pi^* 2 p_y^1$ Bond order $=\frac{1}{2}(10-7)=1.5$

The bond order values of anions of sodium peroxide and potassium super oxide are respectively.

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