The bond dissociation energies of X 2 Y 2 and XY are in the ratio of 1 : 0 .5 : 1 . ΔH for the formation of…

The bond dissociation energies of X2 Y2 and XY are in the ratio of 1 :0.5 :1. ΔH for the formation of XY is -200 kJ mol-1. What will be the bond dissociation energy of X2?
  1. 800 kJ mol-1
  2. 100 kJ mol-1
  3. 200 kJ mol-1
  4. 400 kJ mol-1

Solution

Let B.E. of x2, y2 and xy are x kJ mol-1, 0.5x kJ mol-1 and x kJ mol-1 respectively
12X2+12Y2XY; ΔH=-200 kJ mol-1
ΔH=-200=ΣB.EReactant-ΣB.EProduct
-200=12×x+12×0.5x-1×xx=800kJ  mol
B.E of X2=800 kJ mol-1

Asked in: NEET 2018

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