The bob of a simple pendulum of length ' $L$ ' has a mass ' $m$ ' and charge ' $q$ '. The pendulum is…

The bob of a simple pendulum of length ' $L$ ' has a mass ' $m$ ' and charge ' $q$ '. The pendulum is suspended between the plates of a charged parallel plate capacitor. The direction of electric field is shown in figure. The period of oscillations of the simple pendulum is (acceleration due to gravity $g>q E / m$ )
  1. $2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}$
  2. $2 \pi\left[\frac{\mathrm{L}}{\frac{\mathrm{qE}}{\mathrm{m}}-\mathrm{g}}\right]^{\frac{1}{2}}$
  3. $2 \pi\left[\frac{\mathrm{L}}{\mathrm{g}-\frac{\mathrm{qE}}{\mathrm{m}}}\right]^{\frac{1}{2}}$
  4. $2 \pi\left[\frac{\mathrm{L}}{\mathrm{g}+\frac{\mathrm{qE}}{\mathrm{m}}}\right]^{\frac{1}{2}}$

Solution

Electric force, $\mathrm{F}_{\text {electric }}=\mathrm{qE}$ The effective force, $\begin{aligned} & \mathrm{mg}_{\text {eff }}=\mathrm{mg}-\mathrm{F}_{\text {electric }} \\ & \mathrm{g}_{\text {eff }}=\mathrm{g}-\frac{\mathrm{qE}}{\mathrm{m}} \end{aligned}$ The period of oscillation for a simple pendulum, $\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}$ Time period when pendulum is suspended between the plates, $\begin{aligned} & \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}_{\text {eff }}}} \\ & \mathrm{T}=2 \pi\left[\frac{\mathrm{L}}{\mathrm{g}-\frac{\mathrm{qE}}{\mathrm{m}}}\right]^{\frac{1}{2}} \end{aligned}$

Asked in: MHT CET 2023 (11 May Shift 1)

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