The blue complex formed on addition of conc. $\mathrm{NH}_{4} \mathrm{OH}$ solution to a $\mathrm{Cu}^{2+}$…
- $\left[\mathrm{Cu}\left(\mathrm{NH}_{4}ight)_{4}ight]^{2+}$
- $\left[\mathrm{Cu}\left(\mathrm{NH}_{3}ight)_{2}ight]^{2+}$
- $\left[\mathrm{Cu}\left(\mathrm{NH}_{3}ight)_{4}ight]^{2+}$
- $\left[\mathrm{Cu}\left(\mathrm{NH}_{4}ight)_{2}ight]^{2+}$
Solution
/Asked in: JEE-TOPICTESTS-CHEMISTRY
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